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IBM DB2 9.7 SQL Procedure Developer Sample Questions:
1. Assuming C1 and C2 are cursor type variables, which of the following operations cannot be performed?
A) IF (c1 = c2) THEN ?END;
B) SET c1 = CURSOR FOR VALUES ('a', 'b', 'c');
C) SET c1 = CURSOR FOR SELECT * FROM t;
D) SET c2 = c1;
2. Which statement is true about the data types VARCHAR and VARCHAR2?
A) The VARCHAR2 data type treats empty strings as null; the VARCHAR data type treats empty strings as not null with zero length.
B) The VARCHAR2 data type length is limited to 2000 bytes; the VARCHAR data type length can be up to 32K.
C) The VARCHAR2 data type cannot be used in a database that has not been created in Oracle compatibility mode.
D) The VARCHAR data type cannot be used with a database that has been created in Oracle compatibility mode.
3. Given the following SQL:
Which statement is incorrect?
A) The cursor declaration requires the WITH RETURN TO CLIENT clause in order to return a result set.
B) The cursor declaration requires the WITH RETURN TO CALLER clause in order to return a result set.
C) The procedure declaration requires the DYNAMIC RESULT SETS 1 clause in order to return a result set.
D) The cursor declaration requires the WITH RETURN clause in order to return a result set.
4. Which statement will create a scalar function named FCN1?
A) CREATE FUNCTION fcn1(v1 CHAR(3)) RETURNS CHAR(3) ?CREATE FUNCTION fcn1(v1 CHAR(3)) RETURNS CHAR(3)
B) CREATE FUNCTION fcn1(v1 CHAR(3)) RETURNS ROW CONTAINING CHAR(3) ?CREATE FUNCTION fcn1(v1 CHAR(3)) RETURNS ROW CONTAINING CHAR(3)
C) CREATE SCALAR FUNCTION fcn1(v1 CHAR(3)) RETURNS ROW CONTAINING CHAR(3) ?CREATE SCALAR FUNCTION fcn1(v1 CHAR(3)) RETURNS ROW CONTAINING CHAR(3)
D) CREATE SCALAR FUNCTION fcn1(v1 CHAR(3)) RETURNS CHAR(3) ?CREATE SCALAR FUNCTION fcn1(v1 CHAR(3)) RETURNS CHAR(3)
5. Assuming EMP_ROW and NEW_HIRE have the same user-defined row data type, what is the best way to assign the elements of NEW_HIRE to EMP_ROW?
A) SET emp_row = new_hire;
B) emp_row.rowid = new_hire.rowid;
C) SET emp_row.* = new_hire.*;
D) emp_row.all = new_hire.all;
Solutions:
| Question # 1 Answer: A | Question # 2 Answer: A | Question # 3 Answer: C | Question # 4 Answer: A | Question # 5 Answer: A |








